document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=5637>Question 5637</A>: <I><SPAN STYLE=\"word-break: break-all;\">  If 3x+5x=-8, then x+1=<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2906 by </B><A HREF=/tutors/aboutme.mpl?userid=prince_abubu><B>prince_abubu(198)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=prince_abubu><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2906\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve the first equation first.\r<BR>\n" );
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document.write( "                    3x + 5x = -8<BR>\n" );
document.write( "Combine Like Terms       8x = -8<BR>\n" );
document.write( "Solve for x               x = -1\r<BR>\n" );
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document.write( "Since you found that x = -1, the next part of the question asks you<BR>\n" );
document.write( "what x + 1 is. You'd then plug in that -1 for the x so that you'll have -1 + 1 which = 0. </SPAN>\n" );
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