document.write( "Question 414298: if y varies inversely as the cube of x, and y=64 when x=3,Find the value of x when y=216. \n" ); document.write( "
Algebra.Com's Answer #290581 by ewatrrr(24785)\"\" \"About 
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document.write( "Hi
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document.write( "y varies inversely as the cube  of x  OR y = k/x^3
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document.write( " y=64 when x=3  64 = k/27  k = 1728
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document.write( "Find the value of x when y = 216. 
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document.write( " 216 = 1728/x^3
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document.write( "\"+x%5E3+=+%281728%29%2F216\"
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document.write( "   x^3  = 8
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document.write( "    x = 2 \n" );
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