document.write( "Question 413727: sin2x=-2sinx \n" ); document.write( "
Algebra.Com's Answer #290560 by jsmallt9(3759) ![]() You can put this solution on YOUR website! sin(2x) = -2sin(x) \n" ); document.write( "First let's use the sin(2x) formula so we have everything in terms of just x: \n" ); document.write( "2sin(x)cos(x) = -2sin(x) \n" ); document.write( "Now we'll add 2sin(x) to each side: \n" ); document.write( "2sin(x)cos(x) + 2sin(x) = 0 \n" ); document.write( "And then factor out the GCF which is 2sin(x): \n" ); document.write( "2sin(x)(cos(x) + 1) = 0 \n" ); document.write( "From the Zero Product Property we know that one of these factors must be zero. So: \n" ); document.write( "2sin(x) = 0 or cos(x) + 1 = 0 \n" ); document.write( "Dividing the first equation by 2 and subtracting 1 from the second equation we get: \n" ); document.write( "sin(x) = 0 or cos(x) = -1 \n" ); document.write( "So the solutions will by any value for x that makes the sin zero or the cos -1. If you know your special angles you know that 0, \n" ); document.write( "x = 0 + 2 \n" ); document.write( "or \n" ); document.write( "x = \n" ); document.write( "where \"n\" is any integer. (This is how we include \"all the angles coterminal with...\") (We only need one equation for the angles that are coterminal with |