document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=414282>Question 414282</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The base of a triangular sail is 15m shorter than its height.The area is 92m^2. Find the base and height of the sail. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #290558 by </B><A HREF=/tutors/aboutme.mpl?userid=sudhanshu_kmr><B>sudhanshu_kmr(1152)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sudhanshu_kmr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sudhanshu_kmr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=290558\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "let height = x m ,base = x -15 \r<BR>\n" );
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document.write( "1/2 * x * (x-15) = 92 \r<BR>\n" );
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document.write( "=> x(x-15) = 184\r<BR>\n" );
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document.write( "=> x^2 - 15x -184 =0\r<BR>\n" );
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document.write( "=> x^2 -23x + 8x -184 =0\r<BR>\n" );
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document.write( "=> (x-23)(x+8) = 0\r<BR>\n" );
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document.write( "so, x =23\r<BR>\n" );
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document.write( "height = 23 ,  base = 8 m\r<BR>\n" );
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