document.write( "Question 414207: the perimeter of a rectangle is 104m. The length is 7m more than twice the width.how do i get the dimensions \n" ); document.write( "
Algebra.Com's Answer #290523 by algebrahouse.com(1659)![]() ![]() You can put this solution on YOUR website! \"the perimeter of a rectangle is 104m. The length is 7m more than twice the width.how do i get the dimensions\"\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = width \n" ); document.write( "2x + 7 = length\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Perimeter of a rectangle = (2 x length) + (2 x width)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x + 2(2x + 7) = 104 {perimeter = 2(length + 2(width)} \n" ); document.write( "2x + 4x + 14 = 104 {used distributive property} \n" ); document.write( "6x + 14 = 104 {combined like terms} \n" ); document.write( "6x = 90 {subtracted 14 from both sides} \n" ); document.write( "x = 15 {divided both sides by 6} \n" ); document.write( "2x + 7 = 37 {substituted 15, in for x, into 2x + 7}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "width = 15m and length = 37m \n" ); document.write( "www.algebrahouse.com \n" ); document.write( " |