document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=44122>Question 44122</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you find the remainder from division for the numerator when converting improper fractions into proper fractions? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #29052 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=29052\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let me show you by example...<BR>\n" );
document.write( "Let's say we wish to convert 35/8 to a mixed number...<BR>\n" );
document.write( "So we divide 8 into 35 and get 4 with a remainder of 3...<BR>\n" );
document.write( "We then state our answer as<BR>\n" );
document.write( "4 3/8<BR>\n" );
document.write( "Notice that the divisor (8) remains the denominator and our remainder from the division becomes our numerator... </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );