document.write( "Question 414191: ordered pairs
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document.write( ".3x-0.2y=4
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document.write( ".4x+0.3y=49/23\r
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document.write( "my confusion lies on what I should be plugging in, In class I am learning the three different methods substiituion, elimination and graphing. Well I am totally confused on all of them and do not understand what numbers I should be using to solve. Thank you for any help \n" );
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Algebra.Com's Answer #290504 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! .3x-0.2y=4 \n" ); document.write( ".4x+0.3y=49/23 \n" ); document.write( "--------------------- \n" ); document.write( "Multiply thru 1st by 10 \n" ); document.write( "Multiply thru 2nd by 23 \n" ); document.write( "--------- \n" ); document.write( "3x - 2y = 40 \n" ); document.write( "9.2x+6.9y = 49 \n" ); document.write( "---- \n" ); document.write( "Multiply thru 2nd by 10 \n" ); document.write( "3x - 2y = 40 \n" ); document.write( "92x + 69y = 490 \n" ); document.write( "---- \n" ); document.write( "Multiply thru 1st by 69 \n" ); document.write( "Multiply thru 2nd by 2 \n" ); document.write( "----- \n" ); document.write( "207x - 138y = 2760 \n" ); document.write( "184x + 138y = 980 \n" ); document.write( "---------------------- \n" ); document.write( "Add and solve for \"x\": \n" ); document.write( "391x = 3740 \n" ); document.write( "x = 220/23 \n" ); document.write( "----- \n" ); document.write( "Solve for \"y\": \n" ); document.write( "3x - 2y = 40 \n" ); document.write( "3(220/23) - 2y = 40 \n" ); document.write( "660/23 - 2y = 40 \n" ); document.write( "--- \n" ); document.write( "330/23 - y = 20 \n" ); document.write( "y = (330/23)-20 \n" ); document.write( "y = -130/23 \n" ); document.write( "================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "======================= \n" ); document.write( " \n" ); document.write( " |