document.write( "Question 414191: ordered pairs
\n" ); document.write( ".3x-0.2y=4
\n" ); document.write( ".4x+0.3y=49/23\r
\n" ); document.write( "\n" ); document.write( "my confusion lies on what I should be plugging in, In class I am learning the three different methods substiituion, elimination and graphing. Well I am totally confused on all of them and do not understand what numbers I should be using to solve. Thank you for any help
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Algebra.Com's Answer #290504 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
.3x-0.2y=4
\n" ); document.write( ".4x+0.3y=49/23
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\n" ); document.write( "Multiply thru 1st by 10
\n" ); document.write( "Multiply thru 2nd by 23
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\n" ); document.write( "3x - 2y = 40
\n" ); document.write( "9.2x+6.9y = 49
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\n" ); document.write( "Multiply thru 2nd by 10
\n" ); document.write( "3x - 2y = 40
\n" ); document.write( "92x + 69y = 490
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\n" ); document.write( "Multiply thru 1st by 69
\n" ); document.write( "Multiply thru 2nd by 2
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\n" ); document.write( "207x - 138y = 2760
\n" ); document.write( "184x + 138y = 980
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\n" ); document.write( "Add and solve for \"x\":
\n" ); document.write( "391x = 3740
\n" ); document.write( "x = 220/23
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\n" ); document.write( "Solve for \"y\":
\n" ); document.write( "3x - 2y = 40
\n" ); document.write( "3(220/23) - 2y = 40
\n" ); document.write( "660/23 - 2y = 40
\n" ); document.write( "---
\n" ); document.write( "330/23 - y = 20
\n" ); document.write( "y = (330/23)-20
\n" ); document.write( "y = -130/23
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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