document.write( "Question 414098: An objects altitude, in meters is given by the polynomial h+vt-9.8t, where is the height in meters from which the launch occurs, v is the initial upward speed in meters per second, and the number of seconds for which the rocket is airborne. A pebble is shot upward from the top of a building 183 meters tall. If the initial speed is 39 meters per second, how high above the ground will the pebble be after 3 seconds? \n" ); document.write( "

Algebra.Com's Answer #290442 by Alan3354(69443) $\"\"$ $\"About$

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An objects altitude, in meters is given by the polynomial h+vt-9.8t, where is the height in meters from which the launch occurs, v is the initial upward speed in meters per second, and the number of seconds for which the rocket is airborne. A pebble is shot upward from the top of a building 183 meters tall. If the initial speed is 39 meters per second, how high above the ground will the pebble be after 3 seconds?
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\n" ); document.write( "I don't know where you got that equation, but:
\n" ); document.write( "h(t) = h+vt-9.8t
\n" ); document.write( "h(3) = 183 + 39*3 - 9.8*3
\n" ); document.write( "= 270.6 meters
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\n" ); document.write( "I would use h(t) = h + vt - 4.9t^2
\n" ); document.write( "h(3) = 183 + 39*3 - 4.9*9
\n" ); document.write( "= 255.9 meters
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