document.write( "Question 414094: The sum of the squares of three consecutive positive even integers is 116.
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Algebra.Com's Answer #290441 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!


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document.write( "Hi
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document.write( "Let x,(x+2),(x+4)represent the three consecutive positive even integers 
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document.write( "Question states***
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document.write( "  x^2 + (x+2)^2 + (x+4)^2 = 116
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document.write( "Solving for x
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document.write( "  3x^2 + 12x + 20 = 116
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document.write( "  3x^2 + 12x - 96 = 0
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document.write( "   x^2 + 4x - 32 = 0
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document.write( "factoring
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document.write( " (x + 8)(x-4)=0  Note:SUM of the inner product(8x) and the outer product(-4x) = 4x
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document.write( " (x + 8)=0  x = -8 is an Extraneous solution (not 'positive')
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document.write( " (x-4)=0    x = 4  the three consecutive positive even integers are 4,6,8\r
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document.write( "CHECKING our Answer***
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document.write( " 16 + 36 + 64 = 116 \n" );
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