document.write( "Question 414087: I am stuck on a problem, my teacher only wants me to use the Elimination method
\n" ); document.write( "6x-y=20
\n" ); document.write( "3x-y=7
\n" ); document.write( "I am getting
\n" ); document.write( "x=3 but when I substitute for x in the second equation I get
\n" ); document.write( "6(3) + y = 20
\n" ); document.write( " 18 + y = 20
\n" ); document.write( "but I can't divide each side by 18 evenly, how do I solve for y? \n" ); document.write( "

Algebra.Com's Answer #290434 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "solving by Elimination method
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document.write( "6x-y = 20
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document.write( "3x-y = 7\r
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document.write( " 6x-y = 20
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document.write( "-3x+y = -7   | Multiplying the second Eq by -1 to eliminate y
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document.write( "   3x = 13
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document.write( "    x = 13/3 and y = 6    ( y = 3x -7 from the 2nd origial Eq )
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document.write( "  Solution is (13/3, 6)
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document.write( "CHECKING our Answer***
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document.write( " 6x-y = 20
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document.write( "6*(13/3)- 6 = 26 - 6 = 20 \r
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