document.write( "Question 413968: if the lenght is 2 more than 4 times the width. the perimeter is 158.
\n" ); document.write( "is there something missing, i took it as saying the length is 4 times the width plus 2. is there a formula to break down perimeter backwards?
\n" ); document.write( "i came up with 15.4 as width, and 63.6 as lenght,to give me 158 for perimeter, but mainly thru trial and error method, i took a number times 4 then added 2 till i got 158, i know that wasnt the way it supposed to be done, was wondering what the formula and how work should be shown.
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Algebra.Com's Answer #290396 by Alan3354(69443)\"\" \"About 
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if the lenght is 2 more than 4 times the width. the perimeter is 158.
\n" ); document.write( "is there something missing, i took it as saying the length is 4 times the width plus 2. is there a formula to break down perimeter backwards?
\n" ); document.write( "i came up with 15.4 as width, and 63.6 as lenght,to give me 158 for perimeter, but mainly thru trial and error method, i took a number times 4 then added 2 till i got 158, i know that wasnt the way it supposed to be done, was wondering what the formula and how work should be shown.
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\n" ); document.write( "L = 4W + 2
\n" ); document.write( "Perimeter = 2L + 2W = 158
\n" ); document.write( "2(4W+2) + 2W = 158
\n" ); document.write( "4W+2 + W = 79
\n" ); document.write( "5W = 77
\n" ); document.write( "W = 15.4
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\n" ); document.write( "L = 63.6
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\n" ); document.write( "P = 2L + 2W is the only \"formula\" involved
\n" ); document.write( "PS It's length, not lenght\r
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