document.write( "Question 413968: if the lenght is 2 more than 4 times the width. the perimeter is 158.
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document.write( "is there something missing, i took it as saying the length is 4 times the width plus 2. is there a formula to break down perimeter backwards?
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document.write( "i came up with 15.4 as width, and 63.6 as lenght,to give me 158 for perimeter, but mainly thru trial and error method, i took a number times 4 then added 2 till i got 158, i know that wasnt the way it supposed to be done, was wondering what the formula and how work should be shown. \n" );
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Algebra.Com's Answer #290396 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! if the lenght is 2 more than 4 times the width. the perimeter is 158. \n" ); document.write( "is there something missing, i took it as saying the length is 4 times the width plus 2. is there a formula to break down perimeter backwards? \n" ); document.write( "i came up with 15.4 as width, and 63.6 as lenght,to give me 158 for perimeter, but mainly thru trial and error method, i took a number times 4 then added 2 till i got 158, i know that wasnt the way it supposed to be done, was wondering what the formula and how work should be shown. \n" ); document.write( "------------------ \n" ); document.write( "L = 4W + 2 \n" ); document.write( "Perimeter = 2L + 2W = 158 \n" ); document.write( "2(4W+2) + 2W = 158 \n" ); document.write( "4W+2 + W = 79 \n" ); document.write( "5W = 77 \n" ); document.write( "W = 15.4 \n" ); document.write( "--------- \n" ); document.write( "L = 63.6 \n" ); document.write( "---------- \n" ); document.write( "P = 2L + 2W is the only \"formula\" involved \n" ); document.write( "PS It's length, not lenght\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |