document.write( "Question 413931: If y varies directly as x^3 and y =400 when x=10 ,
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Algebra.Com's Answer #290363 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "If y varies directly as x^3 and y =400 when x=10  400 = k*1000    k = 4/10 = 2/5
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document.write( "a. Find y in terms of x:   y = (2/5)x^3
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document.write( "b. Find y  when  x=5       y = (2/5)125 = 50
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document.write( "c.Find x when y=25 3/5     128/5 = 2/5x^3   x^3 = 64   x = 4 \n" );
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