document.write( "Question 413927: The surface area of a sphere varies directly as the square of a radius.
\n" ); document.write( "a. if the surface area is 16pi when r is 2, find the constant of variation.
\n" ); document.write( "b. Find the surface area when the radius is 5.
\n" ); document.write( "c. Find the radius when the surface area is 48 pi. \n" ); document.write( "

Algebra.Com's Answer #290360 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "The surface area of a sphere varies directly as the square of a radius.
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document.write( "a. if the surface area is 16pi  when r  is 2, find the constant of variation.
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document.write( "   16pi = k*4
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document.write( "    4pi = k\r
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document.write( "b. Find the surface area when the radius is 5. \r
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document.write( "c. Find the radius when the surface area is 48 pi:   kr^2 = 48pi
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document.write( "  r^2 = 48pi/4pi = 12   r = sqrt(12)  or r = 2sqrt(3) \n" );
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