document.write( "Question 413891: Identify the maximum or minimum (vertex), zeros, and axis of symmetry line and show the graph.\r
\n" ); document.write( "\n" ); document.write( " $\"y=%28%281%2F2%29x%5E2%29-x-4\"$
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Algebra.Com's Answer #290351 by bayners123(12) $\"\"$ $\"About$

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maximum/minimum will be turning point. Differentiate the function $\"y=%28%281%2F2%29x%5E2%29-x-4\"$ which is what I think you mean gives you a gradient of x-1, so will have a minimum (minimum as is positive $\"x%5E2\"$ so a bowl shape with a minimum and no maximum) at x=1, at which point y = -4.5.\r
\n" ); document.write( "\n" ); document.write( "zeros;
\n" ); document.write( "x=0, y=-4 clearly
\n" ); document.write( "y=0, $\"x%5E2+-2x+-8+=+0\"$ - I multiplied by 2 to make easier
\n" ); document.write( "0=(x-4)(x+2), x= 4 or -2\r
\n" ); document.write( "\n" ); document.write( "Line of symmetry I am fairly sure it doesn't have as it is a function of x which is an odd function, and x^2 which is even.7\r
\n" ); document.write( "\n" ); document.write( "Drawing the graph should be fine now you know where it crosses the axes. \n" ); document.write( "

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