document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=44053>Question 44053</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jill has $3.50 in nickels and dimes.  If she has 50 coins, how many of each type of coin does she have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #29035 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=29035\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let N be the number of nickels and D be dimes, so that<BR>\n" );
document.write( "N + D = 50<BR>\n" );
document.write( "Their values are 5N and 10D respectively, so that<BR>\n" );
document.write( "5N + 10D = 350<BR>\n" );
document.write( "Now let's multiply the first equation by 5 and subtract it from the second...we get<BR>\n" );
document.write( "5N + 10D = 350<BR>\n" );
document.write( "-(5N + 5D = 250)<BR>\n" );
document.write( "so we have<BR>\n" );
document.write( "5D = 100<BR>\n" );
document.write( "D = 20<BR>\n" );
document.write( "N = 30 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );