document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=413803>Question 413803</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a field is 140 feet. the width is one-sixth of the length. find the width of the field. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #290311 by </B><A HREF=/tutors/aboutme.mpl?userid=phxladyphx@yahoo.com><B>phxladyphx@yahoo.com(18)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=phxladyphx@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=phxladyphx@yahoo.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=290311\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> p=140 feet<BR>\n" );
document.write( "x=width<BR>\n" );
document.write( "6x=length\r<BR>\n" );
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document.write( "x+x+6x+6x=140\r<BR>\n" );
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document.write( "14x=140\r<BR>\n" );
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document.write( "14x/14=140/14\r<BR>\n" );
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document.write( "x=10\r<BR>\n" );
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document.write( "The width is 10 feet and the length is 6x so 6(10) which is 60 feet. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );