document.write( "Question 413303: An experienced bricklayer can work twice as fast as an apprentice bricklayer. After they worked 8 hrs. the experienced one quit. The apprentice required 12 more hrs. to finish the job. How long would it take the experienced one, working alone, to do the job? \n" ); document.write( "
Algebra.Com's Answer #290303 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! An experienced bricklayer can work twice as fast as an apprentice bricklayer. \n" ); document.write( " After they worked 8 hrs. the experienced one quit. \n" ); document.write( " The apprentice required 12 more hrs to finish the job. \n" ); document.write( "How long would it take the experienced one, working alone, to do the job? \n" ); document.write( ": \n" ); document.write( "Let t = experienced bricklayer's time alone to do the job \n" ); document.write( "it says,\"An experienced bricklayer can work twice as fast as an apprentice bricklayer.\"therefore \n" ); document.write( "2x = apprentice time working alone \n" ); document.write( ": \n" ); document.write( "Let the completed job = 1 \n" ); document.write( ": \n" ); document.write( "A typical shared work equation \n" ); document.write( "The apprentice worked a total of: 8 + 12 = 20 hrs \n" ); document.write( " \n" ); document.write( "multiply eq by 2x, results \n" ); document.write( "2(8) + 20 = 2x \n" ); document.write( "16 + 20 = 2x \n" ); document.write( "36 = 2x \n" ); document.write( "x = \n" ); document.write( "x = 18 hr for the experience guy to do the job \n" ); document.write( ": \n" ); document.write( "; \n" ); document.write( "Check solution \n" ); document.write( "8/18 + 20/36 = \n" ); document.write( "4/9 + 5/9 =1 \n" ); document.write( " |