document.write( "Question 413303: An experienced bricklayer can work twice as fast as an apprentice bricklayer. After they worked 8 hrs. the experienced one quit. The apprentice required 12 more hrs. to finish the job. How long would it take the experienced one, working alone, to do the job? \n" ); document.write( "
Algebra.Com's Answer #290303 by ankor@dixie-net.com(22740)\"\" \"About 
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An experienced bricklayer can work twice as fast as an apprentice bricklayer.
\n" ); document.write( " After they worked 8 hrs. the experienced one quit.
\n" ); document.write( " The apprentice required 12 more hrs to finish the job.
\n" ); document.write( "How long would it take the experienced one, working alone, to do the job?
\n" ); document.write( ":
\n" ); document.write( "Let t = experienced bricklayer's time alone to do the job
\n" ); document.write( "it says,\"An experienced bricklayer can work twice as fast as an apprentice bricklayer.\"therefore
\n" ); document.write( "2x = apprentice time working alone
\n" ); document.write( ":
\n" ); document.write( "Let the completed job = 1
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\n" ); document.write( "A typical shared work equation
\n" ); document.write( "The apprentice worked a total of: 8 + 12 = 20 hrs
\n" ); document.write( "\"8%2Fx\" + \"20%2F%282x%29\" = 1
\n" ); document.write( "multiply eq by 2x, results
\n" ); document.write( "2(8) + 20 = 2x
\n" ); document.write( "16 + 20 = 2x
\n" ); document.write( "36 = 2x
\n" ); document.write( "x = \"36%2F2\"
\n" ); document.write( "x = 18 hr for the experience guy to do the job
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\n" ); document.write( "Check solution
\n" ); document.write( "8/18 + 20/36 =
\n" ); document.write( "4/9 + 5/9 =1
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