document.write( "Question 413753: The length of a rectangle is 5 cm longer than twice the width. If the width of the rectangle is 6 cm, find the area of the figure. \n" ); document.write( "
Algebra.Com's Answer #290291 by algebrahouse.com(1659)![]() ![]() You can put this solution on YOUR website! \"The length of a rectangle is 5 cm longer than twice the width. If the width of the rectangle is 6 cm, find the area of the figure.\"\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = width \n" ); document.write( "2x + 5 = length {length is 5 more than twice the width}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Area of a rectangle = length x width \n" ); document.write( "= x(2x + 5) \n" ); document.write( "= 6[2(6) + 5] {problem states width is 6} \n" ); document.write( "= 6(12 + 5) {multiplied 2 by 6} \n" ); document.write( "= 6(17) {added 12 and 5}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Area = 102 cm^2 {multiplied} \n" ); document.write( "www.algebrahouse.com \n" ); document.write( " \n" ); document.write( " |