document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=413116>Question 413116</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve:\r<BR>\n" );
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document.write( "c/5 + 6 = -2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #290248 by </B><A HREF=/tutors/aboutme.mpl?userid=Blue_Skies><B>Blue_Skies(5)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Blue_Skies><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Blue_Skies><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=290248\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">   For equations, you have to solve each step carefully. this is how I would solve this kind of equation:<BR>\n" );
document.write( "   c/5 + 6 = -2<BR>\n" );
document.write( "   c/5 = -2 - 6<BR>\n" );
document.write( "   c/5 = -8<BR>\n" );
document.write( "  The next step is a confusing one. c/5 is a fraction, and the only way to get rid of the 5 is to multiply it by its' reciprocal on both sides. (A reciprocal is basically the number's opposite)<BR>\n" );
document.write( "    (5/1)*(c/5)=-8*(5/1)<BR>\n" );
document.write( "     (ALSO: just a note, 5/1 is a fraction, and it can be simplified as 5, but just so you can fully understand reciprocals, I'm writing it in its' fraction form)<BR>\n" );
document.write( "       The 5's will cancel each other out on c's side of the equation, and 5 will multiply with -8 on the other side, so we will get:<BR>\n" );
document.write( "     c = -40 </SPAN>\n" );
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