document.write( "Question 413620: x raised to 3/2 = 64 \n" ); document.write( "
Algebra.Com's Answer #290225 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E%283%2F2%29%5E%22%22=64\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28sqrt%28x%29%29%5E3=64\"\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28x%29=root%283%2C64%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28x%29=4\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=4%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=16\"\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x=16\"\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you\r
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