document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=43945>Question 43945</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find an equation of the perpendicular bisector of line segment AB: A(-9,-3), <BR>\n" );
document.write( "B(1,-7) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #29018 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=29018\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find an equation of the perpendicular bisector of line segment AB: A(-9,-3),<BR>\n" );
document.write( "B(1,-7)<BR>\n" );
document.write( "WE CAN USE THE PROPERTY OF PERPENDICULAR BISECTOR(LM SAY) TO SOLVE EASILY.ANY POINT ON IT IS EQUIDISTANT FROM A AND B.IF P (X,Y)IS ANY POINT ON IT,THEN<BR>\n" );
document.write( "PA=PB<BR>\n" );
document.write( "PA^2=PB^2<BR>\n" );
document.write( "(X+9)^2+(Y+3)^2=(X-1)^2+(Y+7)^2<BR>\n" );
document.write( "X^2+18X+81+Y^2+6Y+9=X^2-2X+1+Y^2+14Y+49<BR>\n" );
document.write( "20X-8Y+40=0 IS THE EQN. OF PERPENDICULAR BISECTOR.  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );