document.write( "Question 413440: Trying to help my son - but it's a long time since I tackled this subject\r
\n" ); document.write( "\n" ); document.write( "Transpose the formula b=log e t - log e D to make t the subject\r
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\n" ); document.write( "\n" ); document.write( "Show using laws of logarithms that
\n" ); document.write( " I=log 2 (1/p) can be expressed as I = -log 2 (p)
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Algebra.Com's Answer #290152 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
I'm not sure, but I think this is what you wrote:
\n" ); document.write( "\"b+=+ln%28e%5Et%29+-+ln%28e%5ED%29\"
\n" ); document.write( "If so,
\n" ); document.write( "\"b+=+ln%28e%5Et%2Fe%5ED%29\"
\n" ); document.write( "\"b+=+ln%28e%5E%28t+-+D%29%29\"
\n" ); document.write( "\"b+=+t+-+D\"
\n" ); document.write( "\"t+=+b+%2B+D\"
\n" ); document.write( "------------------
\n" ); document.write( "\"I+=+log%282%2C1%2Fp%29\"
\n" ); document.write( "\"I+=+log%282%2Cp%5E-1%29\"
\n" ); document.write( "\"I+=+-log%282%2Cp%29\"
\n" ); document.write( "------------------
\n" ); document.write( "This is the same concept as this easier problem:
\n" ); document.write( "\"K+=+log%281%2F100%29\" (log to the base 10)
\n" ); document.write( "\"K+=+log%2810%5E-2%29\"
\n" ); document.write( "\"K+=+-2%2Alog%2810%29\"
\n" ); document.write( "\"K+=+-2\"\r
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