document.write( "Question 413416: An investment of $1500 paid interest of $45 during a certain period. How much interest would an investment of $2000 invested at the same rate for the same length of time pay?\r
\n" ); document.write( "\n" ); document.write( "This is how I set up my problem.\r
\n" ); document.write( "\n" ); document.write( "1500/45=2000/x
\n" ); document.write( "1500x=2000*45
\n" ); document.write( "1500x=90000
\n" ); document.write( "x=60\r
\n" ); document.write( "\n" ); document.write( "Is this correct?\r
\n" ); document.write( "\n" ); document.write( "Thank you very much.
\n" ); document.write( "

Algebra.Com's Answer #290146 by sudhanshu_kmr(1152)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "yes, it is correct....
\n" ); document.write( "
\n" ); document.write( "
\n" );