document.write( "Question 413360: i need to find the asymptotes of:
\n" ); document.write( "(x/4)2-(y/2)2=1
\n" ); document.write( "the 2 after the parenthesis means its squared.
\n" ); document.write( "i know the equation is y=b/a x, and y=-b/a x
\n" ); document.write( "so a = root 2 and b= root 2, is the answer 1?, can you better explain how to solve the problem?
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Algebra.Com's Answer #290137 by lwsshak3(11628)\"\" \"About 
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i need to find the asymptotes of:
\n" ); document.write( "(x/4)2-(y/2)2=1\r
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\n" ); document.write( "Standard form of given hyperbola is: x^2/a^2-y^2/b^2=1
\n" ); document.write( "What you have here is:
\n" ); document.write( "x^2/16-y^2/4=1
\n" ); document.write( "This is a hyperbola with center at (0,0) that open sideways, that is, its transverse axis is horizontal.
\n" ); document.write( "a^2=16
\n" ); document.write( "a=4
\n" ); document.write( "b^2=4
\n" ); document.write( "b=2
\n" ); document.write( "like you said, the equations of the asymptotes are: y=b/ax and-b/ax.
\n" ); document.write( "For the given hyperbola, y=(2/4)x and y=-(2/4)x
\n" ); document.write( "See the graph below for a visual picture of the asymptotes. You might note that equations of the asymptotes are equations of straight lines of standard form, y=mx+b, with the y-intercept=0 and the slopes, m=b/a and m=-b/a
\n" ); document.write( "..
\n" ); document.write( "y=((x^2-16)/4)^.5
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