document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=413363>Question 413363</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 5 inches less than three times its widths. The perimeter is 86 inches. Find the length and width </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #290100 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=290100\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"The length of a rectangle is 5 inches less than three times its widths. The perimeter is 86 inches. Find the length and width.\"\r<BR>\n" );
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document.write( "x = width<BR>\n" );
document.write( "3x - 5 = length {length is 5 less than 3 times width}\r<BR>\n" );
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document.write( "2x + 2(3x - 5) = 86 {perimeter = (2 x width) + (2 x length)}<BR>\n" );
document.write( "2x + 6x - 10 = 86 {used distributive property}<BR>\n" );
document.write( "8x - 10 = 86 {combined like terms}<BR>\n" );
document.write( "8x = 96 {added 10 to both sides}<BR>\n" );
document.write( "x = 12 {divided both sides by 8}<BR>\n" );
document.write( "3x - 5 = 31 {substituted 12, in for x, into 3x - 5}\r<BR>\n" );
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document.write( "width = 12 in.<BR>\n" );
document.write( "length = 31 in.<BR>\n" );
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