document.write( "Question 413343: How do i use the substitution method for \r
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document.write( "-3x+y=4\r
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document.write( "x+13y=22 \n" );
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Algebra.Com's Answer #290098 by algebrahouse.com(1659)![]() ![]() You can put this solution on YOUR website! How do i use the substitution method for \r \n" ); document.write( "\n" ); document.write( "-3x + y = 4------->y = 3x + 4 {added 3x to both sides}\r \n" ); document.write( "\n" ); document.write( "x + 13y = 22\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + 13(3x + 4) = 22 {substituted 3x + 4, in for y, into bottom equation} \n" ); document.write( "x + 39x + 52 = 22 {used distributive property} \n" ); document.write( "40x + 52 = 22 {combined like terms} \n" ); document.write( "40x = -30 {subtracted 52 from both sides} \n" ); document.write( "x = -3/4 {divided both sides by 40}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = 3x + 4 \n" ); document.write( "y = 3(-3/4) + 4 {substituted -3/4, in for x, into y = 3x + 4} \n" ); document.write( "y = -9/4 + 4 {multiplied 3 by -3/4} \n" ); document.write( "y = -9/4 + 16/4 {got common denominator} \n" ); document.write( "y = 7/4 {combined like terms} \n" ); document.write( "y = 1 3/4 {wrote as a mixed number}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = -3/4 and y = 1 3/4 \n" ); document.write( "www.algebrahouse.com \n" ); document.write( " |