document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=413198>Question 413198</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how would you invest $6400, part at 8% per annum and the remainder at 6% per annum so that at the end of one year the interest from the 8% invesment will be double the interest from the 6% invesment  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #290067 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=290067\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how would you invest $6400, part at 8% per annum and the remainder at 6% per annum so that at the end of one year the interest from the 8% invesment will be double the interest from the 6% invesment\r<BR>\n" );
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document.write( "let x=dollars invested at 8% per annum<BR>\n" );
document.write( "then 6400-x = remaining dollars invested at 6% per annum<BR>\n" );
document.write( "interest earned from 8% investment=twice that of 6% investment<BR>\n" );
document.write( ".08x/.06(6400-x)=2<BR>\n" );
document.write( ".08x=.12(6400-x)=768-.12x<BR>\n" );
document.write( ".2x=768<BR>\n" );
document.write( "x=768/.2=$3840 \r<BR>\n" );
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document.write( "ans:\r<BR>\n" );
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document.write( "You would invest $3840 at 8% interest and $2560 at 6% interest.\r<BR>\n" );
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