document.write( "Question 413165: susan is twice as old as her brother. five years ago susan was 3 times as old as her brother. find her age\r
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Algebra.Com's Answer #290029 by algebrahouse.com(1659)\"\" \"About 
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\"susan is twice as old as her brother. five years ago susan was 3 times as old as her brother. find her age\"\r
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\n" ); document.write( "\n" ); document.write( "x = brother's age now
\n" ); document.write( "2x = Susan's age now\r
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\n" ); document.write( "\n" ); document.write( "x - 5 = brother's age 5 years ago
\n" ); document.write( "2x - 5 = Susan's age 5 years ago\r
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\n" ); document.write( "\n" ); document.write( "2x - 5 = 3(x - 5) {five years ago susan was 3 times as old as her brother}
\n" ); document.write( "2x - 5 = 3x - 15 {used distributive property}
\n" ); document.write( "2x + 10 = 3x {added 15 to both sides}
\n" ); document.write( "x = 10 {subtracted 2x from both sides}
\n" ); document.write( "2x = 20 {Susan's age now}\r
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\n" ); document.write( "\n" ); document.write( "Susan is 20 now
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