document.write( "Question 412995: A picture has a height that is 4/3 it's width. It is to be enlarged to have an area of 192 square inches. What will be the dimensions of the enlargements? \n" ); document.write( "
Algebra.Com's Answer #289956 by shree840(260)\"\" \"About 
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let us say height 4x
\n" ); document.write( "width 3x
\n" ); document.write( "area 4x*3x=12x^2=192
\n" ); document.write( "divide by 12
\n" ); document.write( " x^2=192/12=16
\n" ); document.write( " x=4
\n" ); document.write( " height 4x=4*4=16
\n" ); document.write( " width 3x=3*4=12
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