document.write( "Question 412923: Kindly answer these problems please because i am still quite confused in answering these problem using system of linear equations. \r
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document.write( "2) A diving pool can be filled by a pipe in 10 hrs. if the drain is open. If the pipe was allowed to run with the drain for 2 hrs. and the drain was closed, it would require the pipe 4 more hrs. to fill the pool. How long would it take the pipe to fill the pool if the drain is closed from the start?\r
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document.write( "Thank you in advance! Hoping for your immediate reply.
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Algebra.Com's Answer #289952 by sudhanshu_kmr(1152)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "let assume that pipe fill the tank in x hours,so in one hour 1/x part of tank. \r \n" ); document.write( "\n" ); document.write( "and drain empty the tank in y hours, so in one hour 1/y part of tank.\r \n" ); document.write( "\n" ); document.write( "here obviously value of x is less then y.\r \n" ); document.write( "\n" ); document.write( " portion of tank filled in one hour when both are open = 1/x - 1/y\r \n" ); document.write( "\n" ); document.write( "according to question, \n" ); document.write( " \n" ); document.write( "10(1/x -1/y) = 1 => 10y - 10x = xy \r \n" ); document.write( "\n" ); document.write( "and 2(1/x -1/y) + 4* 1/x = 1 \r \n" ); document.write( "\n" ); document.write( "from first equation we find, y = 10x / (10-x)\r \n" ); document.write( "\n" ); document.write( "now, put this value of second equation, \r \n" ); document.write( "\n" ); document.write( "2( 1/x - (10-x)/10x )+ 4*1/x = 1 \r \n" ); document.write( "\n" ); document.write( "=> 2 * 1/10 + 4/x = 1\r \n" ); document.write( "\n" ); document.write( "after solving, x= 5, y = 10 \r \n" ); document.write( "\n" ); document.write( "x = 5 hours\r \n" ); document.write( "\n" ); document.write( "so, if drain is closed the pipe will fill the pool in 5 hours...\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if any problem, welcome to contact..... \n" ); document.write( " |