document.write( "Question 412924:
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document.write( "Kindly answer these problems please because i am still quite confused in answering these problem using system of linear equations. \r
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document.write( "3) Working together, James and Chris painted their gate in 3 hrs. and 20 min. Working alone, Chris woul need 5 hrs. longer than James to finish the job. How long would it take each of them alone to do the job?\r
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document.write( "Thank you in advance! Hoping for your immediate reply.
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Algebra.Com's Answer #289938 by mananth(16946)![]() ![]() You can put this solution on YOUR website! James takes x hours \n" ); document.write( "1/x of the job he does in 1 hour\r \n" ); document.write( "\n" ); document.write( "chris takes x+5 hours \n" ); document.write( "1/(x+5) of the job he does in 1 hour.\r \n" ); document.write( "\n" ); document.write( "... \n" ); document.write( "Together they take 3 hours 30 minutes = 3 1/3 hour = 10/3 hours \n" ); document.write( ".. \n" ); document.write( "so together they do 3/10 of the job in 1 hour\r \n" ); document.write( "\n" ); document.write( "... \n" ); document.write( "1/x +1/(x+5) = 3/10 \n" ); document.write( "multiply by LCD 10x(x+5) \n" ); document.write( "10x+50+10x = 3x(x+5) \n" ); document.write( "20x+50 = 3x^2+15x \n" ); document.write( "3x^2+15x-20x-50=0 \n" ); document.write( "3x^2-5x-50=0 \n" ); document.write( "3x^2-15x+10x-50=0 \n" ); document.write( "3x(x-5)+10(x-5)=0 \n" ); document.write( "(x-5)(3x+10)=0 \n" ); document.write( "x= 5 hours --- james \n" ); document.write( "Chris ---- 10 hours\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |