document.write( "Question 44074: help please? solve by using the quadratic formula 2x - 4 = 1 - x^2 \n" ); document.write( "
Algebra.Com's Answer #28990 by adamchapman(301)\"\" \"About 
You can put this solution on YOUR website!
rearrang the equation so you have zero on one side of the \"=\" sign.
\n" ); document.write( "This should give \"x%5E2%2B2x-3=0\"
\n" ); document.write( "NOw use the quadratic solver \"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "a = the amount of x squared's = 1
\n" ); document.write( "b = the amount of x's = 2
\n" ); document.write( "c = the number at the end = -3
\n" ); document.write( "put these values in the solver to get
\n" ); document.write( "\"x+=+%28-2+%2B-+sqrt%28+2%5E2-4%2A1%2A%28-3%29+%29%29%2F%282%2A1%29+\"
\n" ); document.write( "\"x+=+%28-2+%2B-+sqrt%28+4%2B12+%29%29%2F2+\"
\n" ); document.write( "\"x+=+%28-2+%2B-+sqrt%28+16+%29%29%2F2+\"
\n" ); document.write( "\"x+=+%28-2+%2B-+4%29%2F2+\"
\n" ); document.write( "\"x+=+-1+%2B-+2+\"
\n" ); document.write( "Therefore x=-3 or x=1\r
\n" ); document.write( "\n" ); document.write( "I hope this helps\r
\n" ); document.write( "\n" ); document.write( "P.S. I am trying to start up my own homework help website. I would be extremely grateful if you would e-mail me some feedback on the help you recieved to adam.chapman@student.manchester.ac.uk
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