document.write( "Question 412827: The perimeter of a rectangle is 90 cm. The length is 15 cm more than four times the width. What is the dimensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #289875 by algebrahouse.com(1659)![]() ![]() You can put this solution on YOUR website! \"The perimeter of a rectangle is 90 cm. The length is 15 cm more than four times the width. What is the dimensions of the rectangle?\"\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = width \n" ); document.write( "4x + 15 = length\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x + 2(4x + 15) = 90 {perimeter equals (2 x width) plus (2 x length)} \n" ); document.write( "2x + 8x + 30 = 90 {used distributive property} \n" ); document.write( "10x + 30 = 90 {combined like terms} \n" ); document.write( "10x = 60 {subtracted 30 from both sides} \n" ); document.write( "x = 6 {divided both sides by 10} \n" ); document.write( "4x + 15 = 39 {substituted 6, in for x, into 4x + 15}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "width = 6cm \n" ); document.write( "length = 39cm \n" ); document.write( "www.algebrahouse.com \n" ); document.write( " |