document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=412820>Question 412820</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2x^2-7x=4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #289865 by </B><A HREF=/tutors/aboutme.mpl?userid=shree840><B>shree840(260)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=shree840><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=shree840><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=289865\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2X^2-7x=4\r<BR>\n" );
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document.write( "2x^2-7x-4=0   you need to multiply 2 with 4 =8 and find factors of 8<BR>\n" );
document.write( "                                                          8x1<BR>\n" );
document.write( "                                                          4x2<BR>\n" );
document.write( "  in this case we can use -8 and 1 so that when added is -7 and multiplied is -\r<BR>\n" );
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document.write( "2x^2-8x +x-4\r<BR>\n" );
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document.write( "2x(x-4)+ 1(x-4)<BR>\n" );
document.write( "(2x+1)(x-4)=0\r<BR>\n" );
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document.write( "for the product to be 0 either first group is 0 or 2nd gr is zero\r<BR>\n" );
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document.write( "if first gr is 0 then 2x+1=0 orx=-1/2<BR>\n" );
document.write( "if 2nd gr is 0   then x-4=0 or x=4 </SPAN>\n" );
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