document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=412793>Question 412793</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An architect designs a rectangular flower garden, the width is exactly 2/3's of the length. If 260 feet of picket fencing r to b used to enclose the garden, find the dimension of the garden...HELP<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #289859 by </B><A HREF=/tutors/aboutme.mpl?userid=shree840><B>shree840(260)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=shree840><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=shree840><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=289859\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let length be x<BR>\n" );
document.write( "width = (2/3)x\r<BR>\n" );
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document.write( "Perimeter = x+x+(2/3)x(2/3)x=260 ft\r<BR>\n" );
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document.write( "          =2x+(4/3)x=260<BR>\n" );
document.write( "           6x+4x=260*3=780  (Multiplying both sides by 3 to get rid of denominator<BR>\n" );
document.write( "          or 10x =780<BR>\n" );
document.write( "               x=78<BR>\n" );
document.write( "         width =2/3* 78=52\r<BR>\n" );
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document.write( "check 78+78+52+52=  260 </SPAN>\n" );
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