document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=44055>Question 44055</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve each of the follwing systems by substitution.<BR>\n" );
document.write( "5x-2y=-5<BR>\n" );
document.write( "y-5x=3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #28985 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=28985\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve each of the follwing systems by substitution.<BR>\n" );
document.write( "5x-2y=-5............I<BR>\n" );
document.write( "y-5x=3......................II...Y=3+5X..........PUT IN EQN.I<BR>\n" );
document.write( "5X-2(3+5X)=-5<BR>\n" );
document.write( "5X-6-10X=-5<BR>\n" );
document.write( "-5X=6-5=1<BR>\n" );
document.write( "X=-1/5<BR>\n" );
document.write( "Y=3+5X=3+5*(-1/5)=3-1=2<BR>\n" );
document.write( "THESE ARE CONSISTENT INDEPENDENT EQNS.AND HENCE HAVE A UNIQUE SOLUTUIN NAMELY...<BR>\n" );
document.write( "=-1/5 AND Y=2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );