document.write( "Question 412513: Each hour I can choose 1 of 4 different classes to attend. After 11 hours, how many combinations of different classes would there be. \n" ); document.write( "
Algebra.Com's Answer #289785 by sudhanshu_kmr(1152) You can put this solution on YOUR website! \n" ); document.write( "If order of classes is not to consider then no. of ways = 14C3 = 364\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if order of classes is to be considered , no. of ways = 4*4*4*.....11 times.\r \n" ); document.write( "\n" ); document.write( "= 4^11\r \n" ); document.write( "\n" ); document.write( " = 4194304\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |