document.write( "Question 412616: George leaves the house on his bike, traveling at 18mph. one hour later his wife June leaves the house and drives the same route at a speed of 45mph. how long will it take June to catch up to George? \n" ); document.write( "

Algebra.Com's Answer #289777 by jjordan95(63) $\"\"$ $\"About$

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$\"18t%2B18=45t\"$
\n" ); document.write( "-
\n" ); document.write( "18t = How far George has traveled during a given time.
\n" ); document.write( "18 = How far George traveled during the hour before June started riding.
\n" ); document.write( "45t = How far June has traveled during a given time.
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\n" ); document.write( "Solving this, you get:
\n" ); document.write( " $\"45t-18t+=+18\"$
\n" ); document.write( " $\"27t=18\"$
\n" ); document.write( " $\"t=18%2F27\"$
\n" ); document.write( "Therefore, the time taken is 18/27 of an hour, which is 2/3 of an hour, or 40 minutes.
\n" ); document.write( " $\"highlight%28t=40%29\"$ minutes, or $\"highlight%28t=2%2F3%29\"$ of an hour. \n" ); document.write( "

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