document.write( "Question 412458: given a normal distribution with a mean of 6000 and standard diviation 1500 what score is at the 30th percentile? \n" ); document.write( "

Algebra.Com's Answer #289706 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "given a normal distribution with a mean of 6000 and standard diviation 1500
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document.write( " what score is at the 30th percentile?
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document.write( "*Note: 
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document.write( "      -.5244 = (x -6000)/1500   |NORMSINV(0.3) = -.5244
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document.write( "     -.5244*1500 + 6000 = x = 5213.4
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