document.write( "Question 412273: Flying against the wind, a jet travels 6440 mi in 7 hours. Flying with the wind, the same jet travels 3780 mi in 3 hours. What is the rate of the jet in still air and what is the rate of the wind? \n" ); document.write( "

Algebra.Com's Answer #289690 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "Let x and y represent the speed of the jet and wind respectively
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document.write( "Question states*** d = r*t
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document.write( " 7x - 7y = 6440
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document.write( " 3x + 3y = 3780 |multiplying thru with 7/3 to eliminate y\r
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document.write( " 7x - 7y = 6440
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document.write( " 7x + 7y = 8820
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document.write( "    14x =  15260
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document.write( "      x = 1090mph, speed of jet
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document.write( "      y = (7*1090 - 6440)/7   |substituting into 1st Eq
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document.write( "      y = 170
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document.write( "CHECKING our Answer***
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document.write( "3*1090 + 3*170 = 3780 \n" );
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