document.write( "Question 412408: Dahn left gas station @ 4:30 and headed south. At 6:00 dazy left the same gas station headed north and traveled 10mph faster than Dahn. at 8:30 Dazy called Dahn and found they were 376 miles apart. How fast was each of them traveling? \n" ); document.write( "
Algebra.Com's Answer #289672 by mananth(16949) You can put this solution on YOUR website! Dahn left gas station @ 4:30 and headed south. At 6:00 dazy left the same gas station headed north and traveled 10mph faster than Dahn. at 8:30 Dazy called Dahn and found they were 376 miles apart. How fast was each of them traveling?\r \n" ); document.write( "\n" ); document.write( "Dahn speed = x mph \n" ); document.write( "Dazy speed = x+10 mph \n" ); document.write( ".. \n" ); document.write( "In 1.5 hours Dahn has traveled 1.5x miles \n" ); document.write( "... \n" ); document.write( "1.5x + 2.5x +2.5(x+20)= 376 \n" ); document.write( "4x+2.5x+50=376 \n" ); document.write( "6.5x=326 \n" ); document.write( "x= 50.1 mph Dahn speed \n" ); document.write( ".. \n" ); document.write( "Liza speed = 70.1 mph \n" ); document.write( " \n" ); document.write( " |