document.write( "Question 412125: Find all values of x over -2pi and under 2pi. The problem is sin x = -.7\r
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document.write( "I know that you first use inverse sine to find the first angle but I don't know how to find the other angle measures. Please help! Thank you!(: \n" );
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Algebra.Com's Answer #289664 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! First we will find the general solution (i.e. all the angles whose sin is -0.7). Then we will use that to find the angles between \n" ); document.write( "To find the general solution we first need the reference angle. And for this we need to use our calculator and the inverse sin function.
\n" ); document.write( "You should get a reference angle of 0.7753974966107531. (Feel free to round this off to whatever accuracy you and/or your teacher think is acceptable.) If you did not get a number close to 0.7753974966107531, then either your calculator is not in radian mode (See \"Calculator mode\" at the end.) or you entered the inverse sin incorrectly (perhaps you entered the minus sign?). \n" ); document.write( "Now we will address the issue of the minus of -0.7. The sin function has negative values for angles that terminate in the 3rd and 4th quadrants. SO we are looking for angles in the 3rd and 4th quadrants whose reference angle is 0.7753974966107531. \n" ); document.write( "In the 3rd quadrant, we add the reference angle and \n" ); document.write( "0.7753974966107531 + \n" ); document.write( "In the 4th quarter, we subtract the reference angle from \n" ); document.write( " \n" ); document.write( "There are an infinite number of angles whose sin is -0.7. But they all have a reference angle of 0.7753974966107531 and they all terminate in either the 3rd or 4th quadrants. To express these infinite solutions (without listing each one) is done is a special way: \n" ); document.write( "x = 3.9169901502005462 + \n" ); document.write( "or \n" ); document.write( "x = 5.5077878105688332 + \n" ); document.write( "The first equation handles all the angles in the 3rd quadrant and the second equation handles all the angles in the 4th quadrant. In these equations, the \"n\" can be any integer. With these infinite possible values for \"n\" we are able to express the infinite solutions for the angles whose sin is -0.7. \n" ); document.write( "You are only interested in the angles between |