document.write( "Question 41884: Help Please\r
\n" ); document.write( "\n" ); document.write( "Use the following table to find the mean, median, mode, standard diviation, and determine if the data appears to be positively, negatively, or normally distributed. Round to the nearest hundredth, if necessary.\r
\n" ); document.write( "\n" ); document.write( "State # 0f Schools
\n" ); document.write( "Florida 456
\n" ); document.write( "Georgia 306
\n" ); document.write( "Maine 160
\n" ); document.write( "Massachusetts 363
\n" ); document.write( "North Carolina 376
\n" ); document.write( "New York 935
\n" ); document.write( "Rhode Island 54
\n" ); document.write( "Virginia 349\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #28966 by stanbon(75887)\"\" \"About 
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Use the following table to find the mean, median, mode, standard diviation, and determine if the data appears to be positively, negatively, or normally distributed. Round to the nearest hundredth, if necessary.
\n" ); document.write( "State # 0f Schools
\n" ); document.write( "Florida 456;Georgia 306;Maine 160;Massachusetts 363;North Carolina 376
\n" ); document.write( "New York 935;Rhode Island 54;Virginia 349 \r
\n" ); document.write( "\n" ); document.write( "mean=374.875
\n" ); document.write( "median is the middle number = 356
\n" ); document.write( "mode is the most frequent value = no mode
\n" ); document.write( "std. dev= 260.496
\n" ); document.write( "Data is skewed to the left. That means there is more data
\n" ); document.write( "to the left of the median than to the right.\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( " \n" ); document.write( "
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