document.write( "Question 412382: MONEY AND INVESTMENT
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document.write( "4) Maria has twice as much money invested at 5% simple annual interest as she does at 4%. If her yearly income from these two investments is Php 350, how much does she have invested at each rate?\r
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document.write( "Thank you in advance! Hoping for your immediate reply. \n" );
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Algebra.Com's Answer #289659 by Theo(13342)![]() ![]() You can put this solution on YOUR website! x = amount of money invested at 4% \n" ); document.write( "2*x = amount of money invested at 5%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "yearly income = 350.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".04*x + .05*2*x = 350\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "factor out the x to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x * (.04 + .05*2) = 350\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x * (.14) = 350\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "divide both sides by .14 to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 350 / .14 = 2500\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that makes 2x = 5000\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "she invested 2500 at 4% and 5000 at 5%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".04 * 2500 + .05 * 5000 = 100 + 250 = 350\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer is confirmed.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "she invested 2500 at 4% and 5000 at 5%.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |