document.write( "Question 412305: Please help me out!
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document.write( "5square root 4x-7=5square root8x+41 \n" );
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Algebra.Com's Answer #289617 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 5square root 4x-7=5square root8x+41 \n" ); document.write( "--- \n" ); document.write( "5*sqrt(4x-7) = 5*sqrt(8x+41) \n" ); document.write( "----- \n" ); document.write( "sqrt(4x-7) = sqrt(8x+41) \n" ); document.write( "--- \n" ); document.write( "4x-7 = 8x+41 \n" ); document.write( "4x = -48 \n" ); document.write( "x = -12 \n" ); document.write( "---- \n" ); document.write( "Checking: \n" ); document.write( "sqrt(4*-12-7) = sqrt(8*-12+41) \n" ); document.write( "--- \n" ); document.write( "sqrt(-55) = sqrt(-55) \n" ); document.write( "======================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============== \n" ); document.write( " |