document.write( "Question 412292: solve by using either process of elimination or substitution
\n" ); document.write( " 3/2x + 3y =2
\n" ); document.write( " 3x - 4y = -16
\n" ); document.write( "

Algebra.Com's Answer #289612 by stanbon(75887)\"\" \"About 
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elimination or substitution
\n" ); document.write( "(3/2)x + 3y =2
\n" ); document.write( "3x - 4y = -16
\n" ); document.write( "----
\n" ); document.write( "Modify:
\n" ); document.write( "3x + 6y = 4
\n" ); document.write( "3x - 4y = -16
\n" ); document.write( "----
\n" ); document.write( "Subtract:
\n" ); document.write( "10y = 20
\n" ); document.write( "y = 2
\n" ); document.write( "-----
\n" ); document.write( "Solve for \"x\":
\n" ); document.write( "3x-4y = -16
\n" ); document.write( "3x - 8 = -16
\n" ); document.write( "3x = -8
\n" ); document.write( "x = -8/3
\n" ); document.write( "==============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "===============
\n" ); document.write( "
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