document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=412290>Question 412290</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find three integers such that the sum of the 1st, two times the second, and three times the third is 82. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #289611 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=289611\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  find three integers such that the sum of the 1st, two times the second, and three times the third is 82<BR>\n" );
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document.write( "I'm going to assume you want consecutive integers.<BR>\n" );
document.write( "---<BR>\n" );
document.write( "1st: x-1<BR>\n" );
document.write( "2nd: x<BR>\n" );
document.write( "3rd: x+1<BR>\n" );
document.write( "------------<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "x-1 + 2x + 3(x+1) = 82<BR>\n" );
document.write( "6x - 2 = 82<BR>\n" );
document.write( "6x = 84<BR>\n" );
document.write( "x = 14<BR>\n" );
document.write( "----<BR>\n" );
document.write( "1st: x-1 = 13<BR>\n" );
document.write( "2nd: x = 14<BR>\n" );
document.write( "3rd: x+1 = 15<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "-<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );