document.write( "Question 412260: How much pure antifreeze must be added to 12 gallons of 20% antifreeze to make a 50% antifreeze solution? \n" ); document.write( "
Algebra.Com's Answer #289592 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How much pure antifreeze must be added to 12 gallons of 20% antifreeze to make a 50% antifreeze solution? \n" ); document.write( "------ \n" ); document.write( "Equation: \n" ); document.write( "active + active = active \n" ); document.write( "0.20*12 + 1.00x = 0.50(12+x) \n" ); document.write( "--- \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "20*12 + 100x = 50*12 + 50x \n" ); document.write( "50x = 30*12 \n" ); document.write( "---- \n" ); document.write( "x = (3/5)12 \n" ); document.write( "x = 36/5 \n" ); document.write( "x = 7 1/5 gallons (amt. of pure antifreeze needed) \n" ); document.write( "================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============== \n" ); document.write( " |