document.write( "Question 412260: How much pure antifreeze must be added to 12 gallons of 20% antifreeze to make a 50% antifreeze solution? \n" ); document.write( "
Algebra.Com's Answer #289592 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
How much pure antifreeze must be added to 12 gallons of 20% antifreeze to make a 50% antifreeze solution?
\n" ); document.write( "------
\n" ); document.write( "Equation:
\n" ); document.write( "active + active = active
\n" ); document.write( "0.20*12 + 1.00x = 0.50(12+x)
\n" ); document.write( "---
\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "20*12 + 100x = 50*12 + 50x
\n" ); document.write( "50x = 30*12
\n" ); document.write( "----
\n" ); document.write( "x = (3/5)12
\n" ); document.write( "x = 36/5
\n" ); document.write( "x = 7 1/5 gallons (amt. of pure antifreeze needed)
\n" ); document.write( "==================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "==============
\n" ); document.write( "
\n" );