document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=412090>Question 412090</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi Stuck with this, please help<BR>\n" );
document.write( "Find the area under y = cos 2t from t = 0 to t = 0.5.\r<BR>\n" );
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document.write( "Thanks Tim </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #289522 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=289522\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the area under y = cos 2t from t = 0 to t = 0.5<BR>\n" );
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document.write( "Integral = sin(2t)/2 + C<BR>\n" );
document.write( "sin(1)/2 - sin(0)/2 = 0.8414/2 - 0<BR>\n" );
document.write( "= 0.4207 sq units<BR>\n" );
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