document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=412097>Question 412097</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Would the set of ordered pairs (x,y) where x = the first name of people in this course<BR>\n" );
document.write( "and y = the birth dates of people in this course define a function?  Why or why not </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #289515 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=289515\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
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document.write( "Possibly.  If no two people in the set of people who are in \"this course\" have the same first name, or for any group of people who are in \"this course\" that do have identical first names the group shares a common birthday, then the set of ordered pairs (x,y) where x = the first name of people in this course and y = the birth dates of people in this course does indeed define a function.  However, if there is just one pair of people who have the same name but different birthdays, then this is not a function.\r<BR>\n" );
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document.write( "In order for a relation to be a function, the output must be unique for any given input.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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